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Question

Question: Let α and β be the roots of the equation \(x^{2} + x + 1 = 0\), the equation whose roots are \(\alph...

Let α and β be the roots of the equation x2+x+1=0x^{2} + x + 1 = 0, the equation whose roots are α19,β7\alpha^{19},\beta^{7} is

A

x2x1=0x^{2} - x - 1 = 0

B

x2x+1=0x^{2} - x + 1 = 0

C

x2+x1=0x^{2} + x - 1 = 0

D

x2+x+1=0x^{2} + x + 1 = 0

Answer

x2+x+1=0x^{2} + x + 1 = 0

Explanation

Solution

Roots of x2+x+1=0x^{2} + x + 1 = 0 are

x=1±142,=1±3i2=ω,ω2x = \frac{- 1 \pm \sqrt{1 - 4}}{2}, = \frac{- 1 \pm \sqrt{3}i}{2} = \omega,\omega^{2}

Take α=ω,β=ω2\alpha = \omega,\beta = \omega^{2}

α19=w19=w,β7=(w2)7=w14=w2\alpha^{19} = w^{19} = w,\beta^{7} = (w^{2})^{7} = w^{14} = w^{2}

∴ Required equation is x2+x+1=0x^{2} + x + 1 = 0