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Question

Real Analysis Question on Sequences and Series

Let (an) be a sequence of real numbers defined by
an={1if n is prime 1if n is not primea_n=\begin{cases} 1 & \text{if } n \text{ is prime}\\\ -1 & \text{if } n \text{ is not prime} \end{cases}
Let bn=annb_n=\frac{a_n}{n} for n ∈ N\N. Then

A

both (an) and (bn) are convergent

B

(an) is convergent but (bn) is NOT convergent

C

(an) is NOT convergent but (bn) is convergent

D

both (an) and (bn) are NOT convergent

Answer

(an) is NOT convergent but (bn) is convergent

Explanation

Solution

The correct option is (C) : (an) is NOT convergent but (bn) is convergent.