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Question

Mathematics Question on Complex Numbers and Quadratic Equations

Let α,β\alpha, \beta be the roots of the equation,(xa)(xb)=c,c0(x - a) (x - b) = c, c \ne 0 .Then the roots of the equation (xα)(xβ)+c=0(x - \alpha) \, (x - \beta) + c = 0 are

A

a, c

B

b, c

C

a, b

D

a + c, b + c

Answer

a, b

Explanation

Solution

Given, α,β\alpha, \beta are the roots of (x - a) (x - b) - c = 0
(xa)(xb)c=(xα)(xβ)\Rightarrow (x - a) (x - b) - c = (x - \alpha) \, (x - \beta)
(xa)(xb)=(xα)(xβ)+c\Rightarrow (x - a) \, (x - b) = (x - \alpha) \, (x - \beta) + c
\Rightarrow a, b are the roots of equation (xα)(xβ)+c(x - \alpha) \, (x - \beta) + c