Question
Question: Let ABC be a triangle with equations of the sides AB, BC and CA respectively x – 2 = 0, y – 5 = 0 an...
Let ABC be a triangle with equations of the sides AB, BC and CA respectively x – 2 = 0, y – 5 = 0 and 5x + 2y –10 = 0. Then the orthocentre of the triangle lies on the line
A
x–y = 0
B
3x –y =1
C
x–2y = 1
D
None of these
Answer
3x –y =1
Explanation
Solution
The given triangle is a right angled triangle. Hence the
orthocentre is the vertex containing the right angle.
⇒ orthocentre is (2, 5) which lies on the lines 3x-y = 1