Question

Let A(1, k), B(1, 1) and C(2, 1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of the triangle is 1 square unit, then the set of values which 'k' can take is given by:

• A. {–3, 1}
• B. {–3, –2}
• C. {1, 3}
• D. {0, 2}

Answer 1

Answer: (A)

{–3, 1}

Answer 2

AB is parallel to y-axis

Ž AB = |k – 1|

BC = 1

$\frac{1}{2}$× 1×|k – 1| = 1

|k – 1| = 2

k –1 = ± 2

k = – 3, 1