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Question

Mathematics Question on Area under Simple Curves

Let
A=(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2A=\\{(x,y) ∈R^2:y≥0,2x≤y≤\sqrt{4-(x-1)^2} \\}
and
B=(x,y)∈R×R:0≤y≤min2x,4−(x−1)2B=\\{(x,y) ∈R\times R:0≤y≤min \\{2x,\sqrt{4-(x-1)^2}\\}\\}
Then the ratio of the area of A to the area of B is

A

π/π-1

B

π+1/π-1

C

π-1/π+1

D

π/π+1

Answer

π-1/π+1

Explanation

Solution

The correct answer is π-1/π+1