Solveeit Logo

Question

Mathematics Question on Sequences and Series of real numbers

Let an=1+12+13++1na_n = 1 + \frac{1}{2} + \frac{1}{3} + \cdots + \frac{1}{n} and bn=k=1n1k2b_n = \sum_{k=1}^{n} \frac{1}{k^2} for all nNn \in \mathbb{N}. Then

A

(an)(a_n) is a Cauchy sequence but (bn)(b_n) is NOT a Cauchy sequence

B

(an)(a_n) is NOT a Cauchy sequence but (bn)(b_n) is a Cauchy sequence

C

both (an)(a_n) and (bn)(b_n) are Cauchy sequences

D

neither (an)(a_n) nor (bn)(b_n) is a Cauchy sequence

Answer

(an)(a_n) is NOT a Cauchy sequence but (bn)(b_n) is a Cauchy sequence

Explanation

Solution

The correct option is (B): (an)(a_n) is NOT a Cauchy sequence but (bn)(b_n) is a Cauchy sequence