Question
Question: Let A = \(\left| \begin{matrix} 1 & \sin\theta & 1 \\ –\sin\theta & 1 & \sin\theta \\ –1 & –\sin\the...
Let A = 1–sinθ–1sinθ1–sinθ1sinθ1, where 0 ≤θ≤2π,
then range of |A| is –
A
(2, 4)
B
(2, 4)
C
(2, 4)
D
All of these
Answer
All of these
Explanation
Solution
|A| = 1 (1 + sin2θ) – sin θ (0) + 1 (sin2θ + 1) = 2 + 2sin2θ
Now as – 1 ≤ sin θ ≤ 1∴ |A| ∈ [2, 4]