Let (a=i+j+2k) and (b=i-2j+3k) be two vectors. Then the unit... | Mathematics | SolveeIt

Let $a=i+j+2k$ and $b=i-2j+3k$ be two vectors. Then the unit vector in the direction of $a-b$ is

$\dfrac{1}{√10}(2j-3k)$

$\dfrac{1}{√10}(3j-k)$

$(3j-k)$

$\dfrac{1}{√5}(2j-3k)$

$\dfrac{-1}{√5}(2j-3k)$

Answer

$\dfrac{1}{√10}(3j-k)$

Explanation

Given data

Here, the two vectors a and b represented as,

$a=i+j+2k$ and $b=i-2j+3k$

then , $a-b =3j-k$

Then according to the question first find unit vector in the direction of $a-b$ ;

$|a-b|=√(3^{2}+1^{2})$

         $=$$√10$

Hence unit vector in the direction of $a-b$ is

$\dfrac{1}{√3}[3j-k]$ (Ans.)

Mathematics Question on Magnitude and Directions of a Vector