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Question

Mathematics Question on Trigonometric Equations

Let a=cos2π7+isin2π7a = cos\frac{2π}7 + isin\frac{2π}7, a = a + a2+a4 and β = a3+ a5 +a6 then the equation whose root are α, β is

A

x2+x+2=0

B

x2+x-2=0

C

x2-x-2=0

D

x2-x+2=0

Answer

x2+x+2=0

Explanation

Solution

The correct answer is(A): x2+x+2=0