Question

Let a circle of x$^2$ + y$^2$ = 16 and line passing through (1,2) cuts the circle at A and B then the locus of the mid-point of AB is:

• A. x2 + y2 + x + y = 0
• B. x2 + y2 - x + 2y = 0
• C. x2 + y2 - x - 2y = 0
• D. x2 + y2 + x + 2y = 0

Answer 1

Answer: (C)

x2 + y2 - x - 2y = 0

Answer 2

The correct option is (C): x$^2$ + y$^2$ - x - 2y = 0