Question

Let a circle C of radius 1 and closer to the origin be such that the lines passing through the point (3, 2) and parallel to the coordinate axes touch it. Then the shortest distance of the circle C from the point (5, 5) is :

• A. $2\sqrt2$
• B. 5
• C. $4\sqrt2$
• D. 4

Answer 1

Answer: (D)

4

Answer 2

Coordinates of the centre will be: $(2, 1)$

Equation of circle: $(x - 2)^2 + (y - 1)^2 = 1$

$QC = \sqrt{(5 - 2)^2 + (5 - 1)^2} = 5$

Shortest distance: $RQ = CQ - CR = 5 - 1 = 4$