Question
Question: Let A = \(\begin{bmatrix} 2 & 3 \\ - 1 & 5 \end{bmatrix}\)if A<sup>–1</sup> = xA + yI<sub>2</sub> t...
Let A = $\begin{bmatrix} 2 & 3 \
- 1 & 5 \end{bmatrix}$if A–1 = xA + yI2 then x and y are
respectively –
A
131, 13−7
B
137,13−1
C
13−1,137
D
13−7,131
Answer
13−1,137
Explanation
Solution
A–1 = 131 [51−32]= x$\begin{bmatrix} 2 & 3 \
- 1 & 5 \end{bmatrix}+y\begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$
Ž 135 = 2x + y, 13−3 =3x
Ž 131 = –x, 132 = 5x + y
x = 13−1, y =137.