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Question: Let A = \(\begin{bmatrix} 2 & 3 \\ - 1 & 5 \end{bmatrix}\)if A<sup>–1</sup> = xA + yI<sub>2</sub> t...

Let A = $\begin{bmatrix} 2 & 3 \

  • 1 & 5 \end{bmatrix}$if A–1 = xA + yI2 then x and y are

respectively –

A

113\frac{1}{13}, 713\frac{- 7}{13}

B

713\frac{7}{13},113\frac{- 1}{13}

C

113\frac{- 1}{13},713\frac{7}{13}

D

713\frac{- 7}{13},113\frac{1}{13}

Answer

113\frac{- 1}{13},713\frac{7}{13}

Explanation

Solution

A–1 = 113\frac { 1 } { 13 } [5312]\begin{bmatrix} 5 & - 3 \\ 1 & 2 \end{bmatrix}= x$\begin{bmatrix} 2 & 3 \

  • 1 & 5 \end{bmatrix}+y+ y \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$

Ž 513\frac{5}{13} = 2x + y, 313\frac{- 3}{13} =3x

Ž 113\frac{1}{13} = –x, 213\frac{2}{13} = 5x + y

x = 113\frac{- 1}{13}, y =713\frac{7}{13}.