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Question

Mathematics Question on Matrices and Determinants

Let A=(112 101 211)A=\begin{pmatrix} 1 & -1 & 2 \\\ -1 & 0 & 1 \\\ 2 & 1 & 1 \end{pmatrix} and let (x1 x2 x3)\begin{pmatrix} x_1 \\\ x_2 \\\ x_3 \end{pmatrix}be an eigenvector corresponding to the smallest eigenvalue of A, satisfying x12+x22+x32=1x^2_1+x^2_2+x^2_3=1. Then the value of |x1| + |x2| + |x3| equals __________ (round off to 2 decimal places)

Answer

The correct answer is 1.70 to 1.76.(approx)