Question

Let A=$\begin{pmatrix} 0&0 &1 \\\ 1&0 &0 \\\ 0&0 &0 \end{pmatrix}$, B=$\begin{pmatrix} 0&1 &0 \\\ 0&0 &1 \\\ 0&0 &0 \end{pmatrix}$ and P=$\begin{pmatrix} 0&1 &0 \\\ x&0 &0 \\\ 0&0 &y \end{pmatrix}$ be an orthogonal matrix such that B=PAP-1 holds. Then

• A. x-1=y
• B. x=1,y=0
• C. x=0,y=1
• D. x=-1,y=0

Answer 1

Answer: (A)

x-1=y

Answer 2

The correct answer is option (A): x-1=y