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Question: Let a be the sum of integer roots of the equation $(x^2 + 4x)^2 - 9(x + 2)^2 = 0$, then the value of...

Let a be the sum of integer roots of the equation (x2+4x)29(x+2)2=0(x^2 + 4x)^2 - 9(x + 2)^2 = 0, then the value of a|a| is

Answer

8

Explanation

Solution

The equation (x2+4x)29(x+2)2=0(x^2 + 4x)^2 - 9(x + 2)^2 = 0 is solved by recognizing it as a difference of squares: (x2+4x)2(3(x+2))2=0(x^2 + 4x)^2 - (3(x + 2))^2 = 0. This expands to (x2+4x3(x+2))(x2+4x+3(x+2))=0(x^2 + 4x - 3(x+2))(x^2 + 4x + 3(x+2)) = 0.

Simplifying the terms gives two quadratic equations:

  1. x2+x6=0    (x+3)(x2)=0    x=3,2x^2 + x - 6 = 0 \implies (x+3)(x-2) = 0 \implies x = -3, 2.
  2. x2+7x+6=0    (x+1)(x+6)=0    x=1,6x^2 + 7x + 6 = 0 \implies (x+1)(x+6) = 0 \implies x = -1, -6.

All roots are integers. The sum of these integer roots is a=(3)+2+(1)+(6)=8a = (-3) + 2 + (-1) + (-6) = -8.

The value of a|a| is 8=8|-8| = 8.