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Question

Quantitative Aptitude Question on Properties of Numbers

Let a,b,ma, b, m and nn be natural numbers such that a>1a >1 and b>1b >1 . If am+bn=144145a^m+b^n = 144^{145} , then the largest possible value of nmn − m is

A

579

B

289

C

580

D

290

Answer

579

Explanation

Solution

Given :
am × bn = 144145 where a > 1 and b > 1.
We can also write 144 as 24 × 32

Therefore, am × bn = 144145 that can be expressed as am × bn = (24 × 32)145
= 2580 × 3290

As we know that 3290 is a natural number, which implies that it can be expressed as a1, where a > 1
Therefore, the least possible value of m is 1.

By the same logic, the largest value of n is 580.
So, the largest value of (n - m) = (580 - 1) = 579
Therefore, the correct option is (A) : 579.