Question

Let a, b, c be such that b (a+c)≠0. If |aa+1a−1−bb+1b−1cc−1c+1|+|a+1b+1c−1a−1b−1c+1(−1)n+2a(−1)n+1b(−1)nc|=0Then the value of n is?

• A. (A) Zero
• B. (B) Any even integer
• C. (C) Any odd integer
• D. (D) Any integer

Answer 1

Answer: (C)

(C) Any odd integer

Answer 2

Explanation:
|aa+1a−1−bb+1b−1cc−1c+1|+|(−1)n+2aa+1a−1(−1)n+1bb+1b−1(−1)ncc−1c+1|=|a+(−1)n+2aa+1a−1−b+(−1)n+1bb+1b−1c+(−1)ncc−1c+1|=0 if n is an odd integer.Hence, the correct option is (C).