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Question

Mathematics Question on Matrices

Let A+B=[414\144]A+B=\begin{bmatrix} 4&1&4\\\1&4&4 \end{bmatrix}and B=[102130]B=\begin{bmatrix} 1&0&-2\\\\-1&3&0 \end{bmatrix}, then A=

A

[312\034]\begin{bmatrix} 3&1&2\\\0&3&4 \end{bmatrix}

B

[512\074]\begin{bmatrix} 5&1&2\\\0&7&4 \end{bmatrix}

C

[312\214]\begin{bmatrix} 3&-1&-2\\\2&1&4 \end{bmatrix}

D

[516\214]\begin{bmatrix} 5&1&6\\\2&1&4 \end{bmatrix}

E

[316\214]\begin{bmatrix} 3&1&6\\\2&1&4 \end{bmatrix}

Answer

[316\214]\begin{bmatrix} 3&1&6\\\2&1&4 \end{bmatrix}

Explanation

Solution

The correct option is (E): [316\214]\begin{bmatrix} 3&1&6\\\2&1&4 \end{bmatrix}