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Question: Let A, B and C be the sets such that \(A \cup B = A \cup C{\text{ and A}} \cap {\text{B = A}} \cap C...

Let A, B and C be the sets such that AB=AC and AB = ACA \cup B = A \cup C{\text{ and A}} \cap {\text{B = A}} \cap C . Show that B=C .

Explanation

Solution

In this particular type of question we need to use the general formula of set i.e. (AB)C=(AC)(BC)(A \cup B) \cap C = (A \cap C) \cup (B \cap C). With this we will be using some of the other basic formulas of set operations. Firstly we will consider AB=ACA \cup B = A \cup C then we will take the intersection of B and C individually and we will take the help of above formulas. Then we will get two equations. After comparing these two equations, we will get our answer.

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Complete step-by-step answer:**

We have,

AB=AC and AB = ACA \cup B = A \cup C{\text{ and A}} \cap {\text{B = A}} \cap C

Let’s consider AB=ACA \cup B = A \cup C

Take the intersection of C on both sides. We get,

(AB)C=(AC)C\Rightarrow (A \cup B) \cap C = (A \cup C) \cap C

But we know that,

(AC)C=C(A \cup C) \cap C = C and (AB)C=(AC)(BC)(A \cup B) \cap C = (A \cap C) \cup (B \cap C)

We will put these two formulas in the above equation.

We get,

(AC)(BC)=C(A \cap C) \cup (B \cap C) = C

This can be written as,

(AB)(BC)=C(A \cap B) \cup (B \cap C) = C ……………(1) (AC=AB)(\therefore A \cap C = A \cap B)

Again AB=ACA \cup B = A \cup C

Now take the intersection of B on both sides. We get

(AB)B=(AC)B\Rightarrow (A \cup B) \cap B = (A \cup C) \cap B

We know that,

(AB)B=B(A \cup B) \cap B = B and (AC)B=(AB)(CB)(A \cup C) \cap B = (A \cap B) \cup (C \cap B)

We will put these two formulas in the above equation.

We get,

B=(AB)(CB)B = (A \cap B) \cup (C \cap B)

(AB)(CB)=B\therefore (A \cap B) \cup (C \cap B)=B

This can be written as,

(AB)(BC)=B(A \cap B) \cup (B \cap C)=B ……………(2) (BC=CB)(\therefore B \cap C= C \cap B)

From the equation (1) and (2), we can see that LHS are the same in both cases.

So we can conclude that our RHS will also be the same.

i.e. B = C

Hence proved.

Note: In these questions we need to recall the general addition formula of two sets which are in union or intersection . We can also use a Venn diagram to get to the required results . Note that in a Venn diagram with sets A and B intersecting with each other if we add sets A and B , we will get the common element of the two sets which we need to subtract once , this is what a general addition rule tells us.