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Question

Mathematics Question on Geometric Progression

Let αα and ββ the roots of equation px2+qxr=0px^2 + qx - r = 0, where P0P≠ 0. If p,q,rp,q,r be the consecutive term of non constant G.P and 1α+1β=34\frac{1}{α} + \frac{1}{β} = \frac{3}{4} then the value of (αβ)2(α - β)^2 is:

Answer

The Correct Answer is: 809\frac{80}{9}