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Question: Let A and B be two sets such that \[n[P(A)] = 8\] and \[n[P(B)] = 4\]. If \((a,2),(b,3),(c,3)\) are ...

Let A and B be two sets such that n[P(A)]=8n[P(A)] = 8 and n[P(B)]=4n[P(B)] = 4. If (a,2),(b,3),(c,3)(a,2),(b,3),(c,3) are in A×BA \times B. Find (i) A and B, where a, b, c are distinct and (ii) A×BA \times B.

Explanation

Solution

We will first use the formula of number of elements in the power set and using that, we will calculate the number of elements in A and B. Now, we already have some elements of A×BA \times B. Using these elements, we can easily find A and B and thus A×BA \times B as well.

Complete step-by-step answer:
We know that if a set (Say) X has xx elements, then n[P(X)]=2xn[P(X)] = {2^x}.
Since, we already have n[P(A)]=8n[P(A)] = 8.
We can write it as:
n[P(A)]=23\Rightarrow n[P(A)] = {2^3}
Hence, A has 3 elements.
Similarly, we are given that n[P(B)]=4n[P(B)] = 4.
We can write it as:
n[P(B)]=22\Rightarrow n[P(B)] = {2^2}
Hence, B has 2 elements.
Now, we are given some elements of A×BA \times B which are (a,2),(b,3),(c,3)(a,2),(b,3),(c,3).
We know that (x,y)X×Y(x,y) \in X \times Y iff xX,yYx \in X,y \in Y.
Therefore, by looking at (a,2),(b,3),(c,3)(a,2),(b,3),(c,3) as elements of A×BA \times B.
We see that a,b,cAa,b,c \in A and 2,3B2,3 \in B.
Since A has 3 elements and a, b and c are given to be distinct. Therefore, A=a,b,cA = \\{ a,b,c\\} .
B also has 2 elements. Therefore, B=2,3B = \\{ 2,3\\}
Now, we know that (x,y)X×Y(x,y) \in X \times Y iff xX,yYx \in X,y \in Y.

Therefore, we have A=a,b,cA = \\{ a,b,c\\} and B=2,3B = \\{ 2,3\\} .
So, A×B=(a,2),(a,3),(b,2),(b,3),(c,2),(c,3)A \times B = \\{ (a,2),(a,3),(b,2),(b,3),(c,2),(c,3)\\} .

Note: The students might wonder how did we use the condition of a, b and c being distinct. But you must remember that if we have elements written in a set form, one element cannot be repeated again and again. It appears only once in the seat. So, if a, b and c or any two of them, if, would have been the same, we would not have been able to get the 3 elements as our set A has.
The students must remember the formula of number of elements in the power set because that plays a major role here. If we would not have known about the number of elements of a set, it would be impossible for us to say what the sets will be.
Must remember: A×B=(a,b):aA,bBA \times B = \\{ (a,b):a \in A,b \in B\\}
This is the definition of the cross product of two non-empty sets A and B.