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Question

Mathematics Question on Bayes' Theorem

Let AA and BB are two events and P(A)=0.3,P(B)=0.4,P(AB)=0.5P \left( A '\right)=0.3, P ( B )=0.4, P \left( A \cap B '\right)=0.5, then P(AB)P ( A \cup B) is.

A

0.5

B

0.9

C

1

D

0.1

Answer

0.9

Explanation

Solution

Given :- P(A)=0.3,P(B)=0.4,P(AB)=0.5P \left( A '\right)=0.3, P ( B )=0.4, P \left( A \cap B'\right)=0.5
P(AB)=P(B)+P(AB)P ( A \cup B )= P ( B )+ P \left( A \cap B '\right)
=P(AB)=0.4+0.5= P ( A \cup B )=0.4+0.5
=0.9=0.9