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Question

Mathematics Question on complex numbers

Let Ξ±=8βˆ’14𝑖α=8βˆ’14𝑖, 𝐴=z∈C:Ξ±zβˆ’Ξ±Λ‰zΛ‰z2βˆ’(zΛ‰)2βˆ’112i=1𝐴=\\{z∈C:\frac {Ξ±zβˆ’\bar Ξ±\bar z}{z^2βˆ’(\bar z)^2βˆ’112i }=1\\} and 𝐡=π‘§βˆˆC:βˆ£π‘§+3π‘–βˆ£=4𝐡={π‘§βˆˆC:|𝑧+3𝑖|=4}. Then βˆ‘π‘§βˆˆπ΄βˆ©π΅(π‘…π‘’Β β‘π‘§βˆ’πΌπ‘šβ‘Β π‘§)βˆ‘_{π‘§βˆˆπ΄βˆ©π΅ }(\text {𝑅𝑒}\ β‘π‘§βˆ’\text {πΌπ‘šβ‘}\ 𝑧) is equal to _____ .

Answer

The answer is 14.