Question

Let A = (–2, –2) and B = (2, –2) be two points and AB subtend an angle of 45ŗ at any point P in the plane in such a way that area of DAPB is 8 sq. unit then no. of possible position (s) of P is-

• A. 1
• B. 2
• C. 4
• D. Infinity

Answer 1

Answer: (C)

4

Answer 2

AB = 4 and area of DAPB = 8

\ $\frac{1}{2}$ × 4 × h = 8

h = 4

P lies on the circle of radius 2$\sqrt{2}$ unit with AB as its chord so there a 4 possible position of P