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Question

Mathematics Question on cartesian products of sets

Let A=1,2,3,5,8,9A=\\{1,2,3,5,8,9\\} Then the number of possible functions f:AAf: A \rightarrow A such that f(mn)=f(m)f(n)f(m \cdot n)=f(m) \cdot f(n) for every m,nAm, n \in A with mnAm \cdot n \in A is equal to______

Answer

f(1)=1;f(9)=f(3)×f(3)
i.e., f(3)=1 or 3
Total function =1×6×2×6×6×1=432
So, the correct answer is 432.