Question
Mathematics Question on Sequence and series
Let a1=b1=1and an=an−1+(n−1), bn=bn−1+an−1, ∀n≥2. If S=n=1∑102nbn and T=n=1∑82n−1n, then 27(2S−T) is equal to ____ .
Answer
The answer is 461.
Let a1=b1=1and an=an−1+(n−1), bn=bn−1+an−1, ∀n≥2. If S=n=1∑102nbn and T=n=1∑82n−1n, then 27(2S−T) is equal to ____ .
The answer is 461.