Solveeit Logo

Question

Mathematics Question on Sequence and series

Let 𝑎1=𝑏1=1𝑎_1=𝑏_1=1and 𝑎𝑛=𝑎𝑛1+(𝑛1)𝑎_𝑛=𝑎_{𝑛−1}+(𝑛−1), 𝑏𝑛=𝑏𝑛1+𝑎𝑛1𝑏_𝑛=𝑏_{𝑛−1}+𝑎_{𝑛−1}, 𝑛2∀𝑛≥2. If 𝑆=𝑛=110𝑏𝑛2𝑛𝑆= \displaystyle\sum_{ 𝑛=1}^{10}\frac {𝑏_𝑛}{2^𝑛} and 𝑇=𝑛=18𝑛2𝑛1𝑇= \displaystyle\sum_{𝑛=1}^{8} \frac {𝑛}{2^{𝑛−1}}, then 27(2𝑆𝑇)2^7(2𝑆−𝑇) is equal to ____ .

Answer

The answer is 461.