Solveeit Logo

Question

Mathematics Question on Sequence and series

Let a1,a2,.....,a10a_1, a_2, ....., a_{10} be a G.P. If a3a1=25\frac{a_3}{a_1} = 25 , then a9a5\frac{a_9}{a_5} equals :

A

2(52)2(5^2)

B

4(52)4(5^2)

C

545^4

D

535^3

Answer

545^4

Explanation

Solution

a1,a2,.....,a10a_1, a_2, ....., a_{10} are in G.P.,G.P.,
Let the common ratio be rr
a3a1=25a1r2a1=25r2=25\frac{a_{3}}{a_{1}} = 25 \Rightarrow \frac{a_{1}r^{2}}{a_{1}} = 25 \Rightarrow r^{2} = 25
a9a5=a1r8a1r4=r4=54\frac{a_{9}}{a_{5} } = \frac{a_{1}r^{8}}{a_{1}r^{4}} =r^{4} = 5^{4}