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Question

Mathematics Question on permutations and combinations

Let A=1,3,7,9,11A = \\{1, 3, 7, 9, 11\\} and B=2,4,5,7,8,10,12B = \\{2, 4, 5, 7, 8, 10, 12\\}. Then the total number of one-one maps f:ABf: A \to B, such that f(1)+f(3)=14f(1) + f(3) = 14, is:

A

180

B

120

C

480

D

240

Answer

240

Explanation

Solution

Sol. Fig

Given sets:

A=1,3,7,9,11andB=2,4,5,7,8,10,12A = \\{1, 3, 7, 9, 11\\} \quad \text{and} \quad B = \\{2, 4, 5, 7, 8, 10, 12\\}

A=1,3,7,9,11A = \\{1, 3, 7, 9, 11\\}

B=2,4,5,7,8,10,12B = \\{2, 4, 5, 7, 8, 10, 12\\}

f(1)+f(3)=14f(1) + f(3) = 14

(i) 2+122 + 12

(ii) 4+104 + 10

2×(2×5×4×3)=2402 \times (2 \times 5 \times 4 \times 3) = 240