Question
Mathematics Question on Binomial theorem
Let (3+x)10 = a0+a1(1+x)+a2(1+x)2+..... a10(1+x)10, where a1, a2, ... a10 are constants. Then the value of a0+a1+a2+.... a10 is equal to
A
220
B
210
C
310
D
211
E
215
Answer
310
Explanation
Solution
The correct option is (C) : 310