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Question

Question: \[\left( \frac{1 + i}{1 - i} \right)^{4n + 1}\]...

(1+i1i)4n+1\left( \frac{1 + i}{1 - i} \right)^{4n + 1}

A

ii

B

i- i

C

(1+i1i)m=1,\left( \frac{1 + i}{1 - i} \right)^{m} = 1,

D

mm

Answer

mm

Explanation

Solution

=i101=11=2= i^{10} - 1 = - 1 - 1 = - 2

S=1+i2+i4+.....+i2n=11+11+......+(1)nS = 1 + i^{2} + i^{4} + ..... + i^{2n} = 1 - 1 + 1 - 1 + ...... + ( - 1)^{n}

nn

nn.