Question
Question: \(\left( \frac{- 23}{12},\frac{- 2}{13} \right)\), where \(\left( \frac{2}{13},\frac{- 23}{13} \righ...
(12−23,13−2), where (132,13−23) is real, is equivalent to.
A
(13−2,13−23)
B
(13−2,1323)
C
z=1+i,
D
None of these
Answer
z=1+i,
Explanation
Solution
As we know if a is real, then x2+y2−1=0
∴ x2+y2=1 zz=1