Question

${{\left[ Co{{F}_{6}} \right]}^{3-}}$ Is a coordination complexion. State the magnetic behavior of the complex.

Answer 1

. By writing the electronic configuration of the center element of the ion we can find out the number of unpaired electrons present in the complex coordinate ion which says the magnetic behavior of the ion.

Complete step by step answer:
The given coordinate complex ion is ${{\left[ Co{{F}_{6}} \right]}^{3-}}$.
The center element of this coordinate complex is Cobalt $\left( Co \right)$ which belongs to the D-block elements also called as the transition elements, oxidation number this element in the given complex ion ${{\left[ Co{{F}_{6}} \right]}^{3-}}$ is plus three $\left( +3 \right)$ that is $C{{o}^{3+}}$.
The atomic number of the center element cobalt is 27 and in the given compound it is having the oxidation number of $\left( +3 \right)$and this means there are only twenty four electrons which participates in the electronic configuration, the electronic configuration of the center element $C{{o}^{3+}}$ is $1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{0}}3{{d}^{6}}$ which can also be written as $t_{2g}^{4}e_{g}^{2}$. Therefore there are totally 4 unpaired electrons; two are in ${{t}_{2g}}$ level and the remaining two are in ${{e}_{g}}$ level. Since there are 4 unpaired electrons present in the given center element of the coordinate complex ion which says the magnetic behavior of the coordinate complex as the paramagnetic behavior.
Therefore the magnetic behavior shown by the given coordinate complex ion is the paramagnetic behavior.

Note: The given coordinate complex ${{\left[ Co{{F}_{6}} \right]}^{3-}}$ is $s{{p}^{3}}{{d}^{2}}$ hybridized and the shape of it is Octahedral and shows the Paramagnetic behavior due to the presence of the unpaired electrons in the different energy levels of the configuration. Only with the help of the unpaired electrons and its orientation present in the given complex coordinate we can find the type of magnetic behavior showing by the compound.