Question
Question: \(\left| \begin{matrix} \log_{3}512 & \log_{4}3 \\ \log_{3}8 & \log_{4}9 \end{matrix} \right|\)× \(\...
log3512log38log43log49× log23log34log83log34=
A
7
B
10
C
13
D
17
Answer
10
Explanation
Solution
(log3512.log49−log43.log38) ×(log23.log34−log83.log34)
= (9−23) × (2−32)= 215× 34= 10