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Question: \[\left| \begin{matrix} a_{1} & ma_{1} & b_{1} \\ a_{2} & ma_{2} & b_{2} \\ a_{3} & ma_{3} & b_{3} \...

a_{1} & ma_{1} & b_{1} \\ a_{2} & ma_{2} & b_{2} \\ a_{3} & ma_{3} & b_{3} \end{matrix} \right| =$$
A

0

B

ma1a2a3ma_{1}a_{2}a_{3}

C

ma1a2b3ma_{1}a_{2}b_{3}

D

mb1a2a3mb_{1}a_{2}a_{3}

Answer

0

Explanation

Solution

∣a1ma1b1a2ma2b2a3ma3b3∣=m∣a1a1b1a2a2b2a3a3b3∣=0\left| \begin{matrix} a_{1} & ma_{1} & b_{1} \\ a_{2} & ma_{2} & b_{2} \\ a_{3} & ma_{3} & b_{3} \end{matrix} \right| = m\left| \begin{matrix} a_{1} & a_{1} & b_{1} \\ a_{2} & a_{2} & b_{2} \\ a_{3} & a_{3} & b_{3} \end{matrix} \right| = 0, {∴C1≡C2}\{\therefore C_{1} \equiv C_{2}\}.