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Question: \(\left| \begin{matrix} a + b & a + 2b & a + 3b \\ a + 2b & a + 3b & a + 4b \\ a + 4b & a + 5b & a +...

a+ba+2ba+3ba+2ba+3ba+4ba+4ba+5ba+6b\left| \begin{matrix} a + b & a + 2b & a + 3b \\ a + 2b & a + 3b & a + 4b \\ a + 4b & a + 5b & a + 6b \end{matrix} \right|=

A

a3 + b3 + c3

B

0

C

a3 + b3 + c3 – 3abc

D

None of these

Answer

0

Explanation

Solution

C2 → C2 – C1

C3 → C3 – C2

= a+bbba+2bbba+4bbb\left| \begin{matrix} a + b & b & b \\ a + 2b & b & b \\ a + 4b & b & b \end{matrix} \right| = 0