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Question

Question: \[\left| \begin{matrix} 13 & 16 & 19 \\ 14 & 17 & 20 \\ 15 & 18 & 21 \end{matrix} \right| =\]...

13 & 16 & 19 \\ 14 & 17 & 20 \\ 15 & 18 & 21 \end{matrix} \right| =$$
A

0

B

– 39

C

96

D

57

Answer

0

Explanation

Solution

Applying C3C3C2C_{3} \rightarrow C_{3} - C_{2}and C2C2C1C_{2} \rightarrow C_{2} - C_{1}, we get

133314331533=0\left| \begin{matrix} 13 & 3 & 3 \\ 14 & 3 & 3 \\ 15 & 3 & 3 \end{matrix} \right| = 0 , {C2C3}\{\because C_{2} \equiv C_{3}\}.