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Question: \[\left| \begin{matrix} 11 & 12 & 13 \\ 12 & 13 & 14 \\ 13 & 14 & 15 \end{matrix} \right| =\]...

11 & 12 & 13 \\ 12 & 13 & 14 \\ 13 & 14 & 15 \end{matrix} \right| =$$
A

1

B

0

C

–1

D

67

Answer

0

Explanation

Solution

Apply C3→C3−C2C_{3} \rightarrow C_{3} - C_{2} and C2→C2−C1C_{2} \rightarrow C_{2} - C_{1}.