Question
Question: \(\left| \begin{matrix} 1 & 1 & 1 \\ mC_{1} & m + 1C_{1} & m + 2C_{1} \\ mC_{2} & m + 1C_{2} & m + 2...
1mC1mC21m+1C1m+1C21m+2C1m+2C2 =
A
m(m + 1)
B
m(m – 1)
C
1
D
0
Answer
1
Explanation
Solution
Put m = 2
= 12C12C213C13C214C14C2 = 121133146
= $\left| \begin{matrix} 0 & 0 & 1 \
- 1 & - 1 & 4 \
- 2 & - 3 & 6 \end{matrix} \right|$
[c1 → c1 – c2; c2 → c2 – c3] = 3 – 2 = 1