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Question: \[\left| \begin{matrix} 0 & a & - b \\ - a & 0 & c \\ b & - c & 0 \end{matrix} \right| =\]...

0 & a & - b \\ - a & 0 & c \\ b & - c & 0 \end{matrix} \right| =$$
A

−2abc- 2abc

B

abcabc

C

0

D

a2+b2+c2a^{2} + b^{2} + c^{2}

Answer

0

Explanation

Solution

$\left| \begin{matrix} 0 & a & - b \

  • a & 0 & c \ b & - c & 0 \end{matrix} \right|$ = 0 (Since value of determinant of skew-symmetric matrix of odd orders is 0).