Question

$\left[ \begin{array}{c} \text{NC} \hspace{10mm} \text{OH}_2 \\ \text{NC} - \text{Co} - \text{NH}_3 \\ \hspace{10mm} \text{NH}_3 \end{array} \right]^+$

$\left[ \begin{array}{c} \text{NH}_3 \hspace{10mm} \text{OH}_2 \\ \text{NC} - \text{Co} - \text{NH}_3 \\ \text{NC} \hspace{10mm} \text{NH}_3 \end{array} \right]^+$

$\left[ \begin{array}{c} \text{H}_3\text{N} \hspace{10mm} \text{CN} \\ \text{H}_3\text{N} - \text{Co} - \text{OH}_2 \\ \text{H}_3\text{N} \hspace{10mm} \text{CN} \end{array} \right]^+$

Answer 1

Geometric isomers

Answer 2

The three given complexes have the same chemical formula, $[\text{Co(CN)}_2\text{(NH}_3)_3\text{(H}_2\text{O)}]^+$ but different spatial arrangements of ligands around the central cobalt ion. This difference in arrangement, while maintaining the same connectivity, defines them as geometric isomers.