Question

$\left( 1 + \frac{1}{2!} + \frac{1}{4!} + .... \right)\left( 1 + \frac{1}{3!} + \frac{1}{5!} + .... \right) =$

• A. $e^{4}$
• B. $\frac{e^{2} - 1}{e^{2}}$
• C. $\frac{e^{4} - 1}{4e^{2}}$
• D. $\frac{e^{4} + 1}{4e^{2}}$

Answer 1

Answer: (C)

$\frac{e^{4} - 1}{4e^{2}}$

Answer 2

$\frac{(\log 3)^{3}}{3}$

$\frac{\log(3^{3})}{6}$.