Question
Question: \[\lbrack ikj\rbrack + \lbrack kji\rbrack + \lbrack jki\rbrack\]...
[ikj]+[kji]+[jki]
A
1
B
3
C
– 3
D
– 1
Answer
– 1
Explanation
Solution
[ikj]+[kji]+[jki]=[ikj]+[ikj]−[ikj]=[ikj]=−1.
[ikj]+[kji]+[jki]
1
3
– 3
– 1
– 1
[ikj]+[kji]+[jki]=[ikj]+[ikj]−[ikj]=[ikj]=−1.