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Question: L'' (x) \> 0 " x Ī R and g(x) = f(2 – x) + f(4 + x). Then g(x) is increasing in –...

L'' (x) > 0 " x Ī R and g(x) = f(2 – x) + f(4 + x).

Then g(x) is increasing in –

A

(– , – 1)

B

(– , 0)

C

(– 1, )

D

None

Answer

(– 1, )

Explanation

Solution

f '' (x) > 0 " x Ī R Ž f ' (x) is increasing " x Ī R

g ' (x) = – f ' (2 – x) + f ' (4 + x)

If g ' (x) > 0, then

f ' (4 + x) > f ' (2 – x)

Ž 4 + x > 2 – x

2x > – 2

x > – 1 Ž (–1, )

g(x) is increasing in (–1, )