Question

L-isomer of a compound ‘A’ $(C_4H_8O_4)$ gives a positive test with $[Ag(NH_3)^2]^+$. Treatment of ‘A’ with acetic anhydride yields triacetate derivative. Compound ‘A’ produces an optically active compound (B) and an optically inactive compound (C) on treatment with bromine water and $HNO_3$ respectively. Compound (A) is:

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

When(A) is given heat with acetic anhydride, acetylation occurs and $–OH$ group is replaced by and hence, triacetate is formed.

Hence, the correct option is (A).