Question
Question: L and M are the two points with position vectors \(2\overrightarrow a - \overrightarrow b \) and \(\...
L and M are the two points with position vectors 2a−b and a+2b respectively. Write the position vector of a point N which divides the line segment LM in the ratio 2:1 externally.
Solution
Consider 'R' be the position vector of a point N which divides the line LM in the ratio 2:1 externally which can be found out by formula R=m−nmM−nL.
Complete step-by-step solution -
Given data:
L and M are the two points with position vectors 2a−b and a+2b respectively.
So, L=2a−b and M=a+2b
Now consider a position vector (say R) of point N which divides the line segment LM in the ratio 2:1 externally.
Now as we know that this position vector R is calculated as, R=m−nmM−nL.................... (1), where m and n are the values of the ratio which divide the line externally, i.e. m: n = 2: 1.
Therefore, m = 2, and n = 1.
Now substitute the values we have,
⇒R=2−12(a+2b)−1(2a−b)
Now simplify this we have,
⇒R=1(2a+4b)−1(2a−b)
⇒R=2a+4b−2a+b
⇒R=5b
So this is the required position vector of a point N which divides the line segment LM in the ratio 2:1 externally. So this is the required answer.
Note: Whenever we face such types of questions the key concept we have to remember is that always recall the position vector formula if a point N divides the line segment LM in the ratio m:n externally which is stated above so simply substitute the values in this formula and simplify we will get the required answer.