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Question: Kp for the reaction : CO2(g) + H2(g) CO(g) + H2O(g) is found to be 160 at a given temperature .Orig...

Kp for the reaction :

CO2(g) + H2(g) CO(g) + H2O(g) is found to be 160 at a given temperature .Originally equal number of moles of H2 and CO2 were placed in the flask . At equilibrium, the pressure of H2 is 1.20 atm. What is the partial pressure of CO and H2O?

A

4.80 atm each

B

9.60 atm each

C

2.40 atm each

D

1.20 atm each

Answer

4.80 atm each

Explanation

Solution

CO2+H2\mathrm { CO } _ { 2 } + \mathrm { H } _ { 2 } CO+H2O\mathrm { CO } + \mathrm { H } _ { 2 } \mathrm { O }

Kp=PCOPH2OPCO2PH2\mathrm { K } _ { \mathrm { p } } = \frac { \mathrm { P } _ { \mathrm { CO } } \cdot \mathrm { P } _ { \mathrm { H } _ { 2 } \mathrm { O } } } { \mathrm { P } _ { \mathrm { CO } _ { 2 } } \cdot \mathrm { P } _ { \mathrm { H } _ { 2 } } } s

PCOPH2O=16×120×1.20\mathrm { P } _ { \mathrm { CO } } \cdot \mathrm { P } _ { \mathrm { H } _ { 2 } \mathrm { O } } = 16 \times 120 \times 1.20