Question

$KMnO _4$ oxidises $I ^{-}$in acidic and neutral/faintly alkaline solution, respectively, to

• A. $IO _3^{-} \& IO _3^{-}$
• B. $I _2 \& IO _3^{-}$
• C. $I _2 \& I _2$
• D. $IO _3^{-} \& I _2$

Answer 1

Answer: (B)

$I _2 \& IO _3^{-}$

Answer 2

The correct answer is (B) : $I _2 \& IO _3^{-}$
In acidic medium
2MnO4−​+10I−+16H+→2Mn2++5I2​+8H2​O
In neutral/faintly alkaline solution
2MnO4−​+I−+H2​O→2MnO2​+2OH−+IO3−​