Question

$KMnO_4$ gets reduced to

• A. $K_2MnO_4$ in neutral medium
• B. $MnO_2$ in acidic medium
• C. $Mn^{2+}$ in alkaline medium
• D. $MnO_2$ in neutral medium.

Answer 1

Answer: (D)

$MnO_2$ in neutral medium.

Answer 2

$KMnO_4$ gets reduced to $MnO_2$ in neutral medium. ${2KMnO4 + H2O -> 2MnO2 + 2KOH + 3[O]}$ or ${MnO4^{-} + 2H2O + 3e^{-} -> MnO2 + 4OH^{-}}$ In alkaline mediun, it gets reduced to $MnO_2$ while in acidic medium it gets reduced to $Mn^{2+}$ ions.