( KMnO\_4 ) gets reduced to | Chemistry | SolveeIt

Question

$KMnO_4$ gets reduced to

$K_2MnO_4$ in neutral medium

$MnO_2$ in acidic medium

$Mn^{2+}$ in alkaline medium

$MnO_2$ in neutral medium

Answer

$MnO_2$ in neutral medium

Explanation

Solution

$KMnO_4$ is a powerful oxidising agent and gets reduced to
$(i)\, MnO_2$ in neutral medium.
$2KMnO_4 + H_2O {->} 2KOH + 2MnO_2 + 3[O]$
$(ii)\, K_2MnO_4$ in alkaline medium.
$2KMnO4 + 2KOH {->} 2K_2MnO_4$
$+ H_2O + [O]$
$(iii) \,Mn^{2+}$ in acidic medium.
$MnO_4^- + 8H^+ + 5e^- {->} Mn^{2+} + 4H_2O$

Chemistry Question on d block elements

Solution